McGraw Hill Math Grade 5 Chapter 10 Lesson 13 Answer Key Problem Solving: Using Formulas

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 13 Problem Solving: Using Formulas are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 13 Problem Solving: Using Formulas

Solve.

Solve. Use the formulas V= (l × w) × h, V = B × h, or A = l × w if necessary.

Question 1.
A large fish pond is 5 meters long, 4 meters wide, and 12 centimeters deep. What is the volume of the pond in centimeters?
Answer:
2,400.000 cm³

Question 2.
A rectangular pool has a base area of 600 ft². The total volume of the pool is 4,800 ft³. How deep is the pool?
Answer:
Given rectangular pool,
Area of base (b) = 600 ft²
Total volume of the pool (v) = 4,800 ft³
Deep of the pool (h)= ?
v = b x h
4,800 ft³ = 600 ft² x h
4,800 ft³/600 ft² = h
8 feet = h
The pool is 8 feet deep.

Question 3.
A store sells dragon figures in 10-inch cube boxes. How many boxes of figures can fit on a shelf that is 30 inches long, 20 inches high, and 30 inches wide?
Answer:

Question 4.
Dylan covers the rectangular floor of his room with 24 square meters of carpet The length of the room is 6 meters. What is the width of the room?
Answer:
Area of the rectangular floor (A)= 24 square meters
Length of the room (l) = 6 meters
Width of the room (w) = ?
A = l x w
24 m² = 6 m x w
24 m² /6 m= w
4 m = w
Width of the room is 4 meters.

Use the table for exercise 5.

Question 5.
How much greater in volume is the backpack than the tote?
Answer:
Volume of Tote (V) = 16 in x 15 in x 12 in = 2,880 in³
Volume of Backpack (V) = 20 in x 15 in x 10 in = 3,000 in³
3,000 in³ – 2,800 in³ = 120 in³
The volume of backpack is 120 in³ greater than the tote.