All the solutions provided in **McGraw Hill Math Grade 5 Answer Key PDF Chapter 10 Lesson 13 Problem Solving: Using Formulas **are as per the latest syllabus guidelines.

## McGraw-Hill Math Grade 5 Answer Key Chapter 10 Lesson 13 Problem Solving: Using Formulas

**Solve.**

**Solve. Use the formulas V= (l × w) × h, V = B × h, or A = l × w if necessary.**

Question 1.

A large fish pond is 5 meters long, 4 meters wide, and 12 centimeters deep. What is the volume of the pond in centimeters?

Answer:

2,400.000 cm^{3}

Question 2.

A rectangular pool has a base area of 600 ft^{2}. The total volume of the pool is 4,800 ft^{3}. How deep is the pool?

Answer:

Given rectangular pool,

Area of base (b) = 600 ft^{2}

Total volume of the pool (v) = 4,800 ft^{3}

Deep of the pool (h)= ?

v = b x h

4,800 ft^{3 }= 600 ft^{2 }x h

4,800 ft^{3}/600 ft^{2 }= h

**8 feet = h**

The pool is **8 feet** deep.

Question 3.

A store sells dragon figures in 10-inch cube boxes. How many boxes of figures can fit on a shelf that is 30 inches long, 20 inches high, and 30 inches wide?

Answer:

Question 4.

Dylan covers the rectangular floor of his room with 24 square meters of carpet The length of the room is 6 meters. What is the width of the room?

Answer:

Area of the rectangular floor (A)= 24 square meters

Length of the room (l) = 6 meters

Width of the room (w) = ?

A = l x w

24 m^{2 }= 6 m x w

24 m^{2 }/6 m= w

**4 m = w**

Width of the room is 4 meters.

**Use the table for exercise 5.**

Question 5.

How much greater in volume is the backpack than the tote?

Answer:

Volume of Tote (V) = 16 in x 15 in x 12 in = **2,880 in ^{3}**

Volume of Backpack (V) = 20 in x 15 in x 10 in =

**3,000 in**

^{3}3,000 in

^{3}– 2,800 in

^{3 }= 120 in

^{3}

The volume of backpack is 120 in

^{3 }greater than the tote.