Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers

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Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers

Texas Go Math Grade 6 Module 2 Are you ready? Answer Key

Write each improper fraction as a mixed number.

Question 1.
\(\frac{7}{2}\)
Answer:
Firstly, we will write this improper fraction as a sum of proper fractions(ones) plus one which is not proper
SecondLy, we wilt exchange proper fractions with ones!
Thirdly, we will add them
Final soLution wilt be: mixed number.

\(\frac{7}{2}\) = \(\frac{2}{2}+\frac{2}{2}+\frac{2}{2}+\frac{1}{2}\)
= 1 + 1 + 1 + \(\frac{1}{2}\)
= 3 + \(\frac{1}{2}\)
= 3\(\frac{1}{2}\)

Question 2.
\(\frac{12}{5}\)
Answer:
Firstly, we will write this improper fraction as a sum of proper fractions(ones) plus one which is not proper
Secondly, we will exchange proper fractions with ones!
Thirdly, we will add them
Final solution will be: mixed number

\(\frac{12}{5}\) = \(\frac{5}{5}+\frac{5}{5}+\frac{2}{5}\)
= 1 + 1 + \(\frac{2}{5}\)
= 2 + \(\frac{2}{5}\)
= 2\(\frac{2}{5}\)

Question 3.
\(\frac{11}{7}\)
Answer:
Firstly, we will write this improper fraction as a sum of proper fractions(ones) plus one which is not proper
SecondLy, we wiLl exchange proper fractions with ones!
Thirdly, we will add them
Final solution will be: mixed number

\(\frac{11}{7}\) = \(\frac{7}{7}+\frac{4}{7}\)
= 1 + \(\frac{4}{7}\)
= 1\(\frac{4}{7}\)

Question 4.
\(\frac{15}{4}\)
Answer:
Firstly, we will write this improper fraction as a sum of proper fractions(ones) plus one which is not proper
Secondly, we will exchange proper fractions with ones!
Thirdly, we will add them.
Final solution will be: mixed number.

\(\frac{15}{4}\) = \(\frac{4}{4}+\frac{4}{4}+\frac{4}{4}+\frac{3}{4}\)
= 1 + 1 + 1 + \(\frac{3}{4}\)
= 3 + \(\frac{3}{4}\)
= 3\(\frac{3}{4}\)

Write each mixed number as an improper fraction.

Question 5.
2\(\frac{1}{2}\)
Answer:
Firstly, we will write the whole number as a sum of ones.
Secondly, we will use the denominator to find corresponding fractions for ones.
Thirdly, we will. calculate sum of numerators!
To reach our final solution: improper fraction.

2\(\frac{1}{2}\) = 1 + 1 + \(\frac{1}{2}\)
= \(\frac{2}{2}+\frac{2}{2}+\frac{1}{2}\)
= \(\frac{5}{2}\)

Question 6.
4\(\frac{3}{5}\)
Answer:
Firstly, we will write the whole number as a sum of ones.
Secondly, we will use the denominator to find corresponding fractions for ones.
Thirdly, we will calculate sum of numerators!
To reach our final solution: improper fraction.

4\(\frac{3}{5}\) = 1 + 1 + 1 + 1 + \(\frac{3}{5}\)
= \(\frac{5}{5}+\frac{5}{5}+\frac{5}{5}+\frac{5}{5}+\frac{3}{5}\)
= \(\frac{23}{5}\)

Question 7.
3\(\frac{4}{9}\)
Answer:
Firstly, we will write the whole number as a sum of ones.
Secondly, we will use the denominator to find corresponding fractions for ones.
Thirdly, we will calculate sum of numerators!
To reach our final solution: improper fraction.

3\(\frac{4}{9}\) = 1 + 1 + 1 + \(\frac{4}{9}\)
= \(\frac{9}{9}+\frac{9}{9}+\frac{9}{9}+\frac{4}{9}\)
= \(\frac{31}{9}\)

Question 8.
2\(\frac{5}{7}\)
Answer:
Firstly, we will write the whole number as a sum of ones.
Secondly, we will use the denominator to find corresponding fractions for ones.
Thirdly, we will calculate sum of numerators!
To reach our final solution: improper fraction.

2\(\frac{5}{7}\) = 1 + 1 + \(\frac{5}{7}\)
= \(\frac{7}{7}+\frac{7}{7}+\frac{5}{7}\)
= \(\frac{19}{7}\)

Find the least common denominator.

Question 9.
\(\frac{1}{2}\) and \(\frac{3}{5}\) _________
Answer:
Firstly, we will list multiples of each denominator.
Secondly, we will highlight common multiples!
Thirdly, we will determine, which is the least common denominator!
Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers 2
Least Common denominator is 10

Question 10.
\(\frac{1}{6}\) and \(\frac{3}{8}\) _________
Answer:
Firstly, we will list multiples of each denominator.
Secondly, we will highlight common multiples!
Thirdly, we will determine, which is the least common denominator!
Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers 3
Least Common denominator is 24

Question 11.
\(\frac{9}{10}\) and \(\frac{7}{12}\) _________
Answer:
Firstly, we will list multiples of each denominator.
Secondly, we will highlight common multiples!
Thirdly, we will determine, which is the least common denominator!
Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers 4
Least Common denominator is 60

Question 12.
\(\frac{4}{9}\) and \(\frac{5}{12}\) _________
Answer:
Firstly, we will list multiples of each denominator.
Secondly, we will highlight common multiples!
Thirdly, we will determine, which is the least common denominator!
Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers 5
Least Common denominator is 36

Texas Go Math Grade 6 Module 2 Reading Start-Up Answer Key

Visualize Vocabulary
Use the ✓ words to complete the web. You may put more than one word in each box.

Texas Go Math Grade 6 Module 2 Answer Key Rational Numbers 1

Understand Vocabulary

Fill in each blank with the correct term from the preview words.

Question 1.
A _________________ is any number that can be written as a ratio of two integers.
Answer:
A rational is any number that can be written as a ratio of two integers!

Question 2.
A _________________ is used to show the relationships between groups.
Answer:
A Venn diagram is used to show the relationships between groups.

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