Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 8 Module 10 Quiz Answer Key.

## Texas Go Math Grade 6 Module 10 Quiz Answer Key

**10.1 Exponents**

**Find the value of each power.**

Question 1.

7^{3}

Answer:

Solution to this example is given below 7^{3}

Identify the base and the exponent.

The base is 7 and the exponent is 3.

Final Solution:

Evaluate: 7^{3} = 7 × 7 × 7 = 343

Question 2.

9^{2}

Answer:

Solution to this example is given below 9^{2}

Identify the base and the exponent.

The base is 9 and the exponent is 2.

Final Solution:

Evaluate: 9^{2} = 9 × 9 = 81

Question 3.

\(\left(\frac{7}{9}\right)^{2}\)

Answer:

Solution to this example is given below \(\left(\frac{7}{9}\right)^{2}\)

Identify the base and the exponent.

The base is \(\frac{7}{9}\) and the exponent is 2.

Final Solution:

Evaluate: \(\left(\frac{7}{9}\right)^{2}\) = \(\frac{7}{9} \times \frac{7}{9}\) = \(\frac{79}{81}\)

Question 4.

\(\left(\frac{1}{2}\right)^{6}\)

Answer:

Solution to this example is given below \(\left(\frac{1}{2}\right)^{6}\)

Identify the base and the exponent.

The base is \(\frac{1}{2}\) and the exponent is 6.

Final Solution:

Evaluate: \(\left(\frac{1}{2}\right)^{6}\) = \(\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}\) = \(\frac{1}{64}\)

Question 5.

\(\left(\frac{2}{3}\right)^{3}\)

Answer:

Solution to this example is given below \(\left(\frac{2}{3}\right)^{3}\)

Identify the base and the exponent.

The base is \(\frac{2}{3}\) and the exponent is 3.

Final Solution:

Evaluate: \(\left(\frac{2}{3}\right)^{3}\) = \(\frac{2}{3} \times \frac{2}{3} \times \frac{2}{3}\) = \(\frac{8}{27}\)

Question 6.

(- 3)^{5}

Answer:

Simplify the given expression by identifying the base and exponent

The base is – 3 and the exponent is 5.

= (- 3) × (- 3) × (- 3) × (- 3) × (- 3) multiply the base by itself five times

= – 243

The simplified expression is – 243.

Question 7.

(- 2)^{4}

Answer:

Simplify the given expression by identifying the base and exponent.

The base is – 2 and the exponent is 4.

= (- 2) × (- 2) × (- 2) × (- 2) multiply the base by itself four times

= 16

The simplified expression is 16.

Question 8.

1.4^{2}

Answer:

Solution to this example is given below 1.4^{2}

Identify the base and the exponent.

The base is 1.4 and the exponent is 2.

Final Solution:

Evaluate: 1.4^{2} = 1.4 × 1.4 = 1.96

**10.2 Prime Factorization**

**Find the factors of each number.**

Question 9.

96 _________________

Answer:

List the factors of 96

- 96 = 1 × 96
- 96 = 2 × 48
- 96 = 3 × 32
- 96 = 4 × 24
- 96 = 6 × 16
- 96 = 8 × 12

The factors of 96 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48 and 96.

Question 10.

120 ________________

Answer:

List the factors of 120

- 120 = 1 × 120
- 120 = 2 × 60
- 120 = 3 × 40
- 120 = 5 × 24
- 120 = 6 × 20
- 120 = 8 × 15
- 120 = 10 × 12

The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 60 and 120.

**Find the prime factorization of each number.**

Question 11.

58 ________________

Answer:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 58 are 2, and 29.

The prime factorization of 58 is 2 × 29

Question 12.

212 _______________

Answer:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 212 are 2, 2 and 53.

The prime factorization of 212 is 2 × 2 × 53 or 2^{2} × 53

Question 13.

2,800 ______________

Answer:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 2800 are 2, 2, 2, 2, 5, 5 and 7.

The prime factorization of 2800 is 2 × 2 × 2 × 2 × 5 × 5 × 7 or 2^{4} × 5^{2} × 7

Question 14.

900 ______________

Answer:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 900 are 2, 2, 3, 3, 5 and 5.

The prime factorization of 2800 is 2 × 2 × 3 × 3 × 5 × 5 or 2^{2} × 3^{2} × 5^{2}

**10.3 Order of Operations**

**Simplify each expression using the order of operations.**

Question 15.

(21 – 3) ÷ 3^{2}

Answer:

Solution to this example is given below

(21 – 3) ÷ 3^{2}

(21 – 3) ÷ 3^{2} = (21 – 3) ÷ 9 Evaluate 3^{2}

= 18 ÷ 9 Perform operations inside parentheses.

= 2 Divide.

= 2

Question 16.

7^{2} × (6 ÷ 3)

Answer:

Solution to this example is given below

7^{2} × (6 ÷ 3)

7^{2} × (6 ÷ 3)> = 49 × (6 ÷ 3) Evaluate 7^{2}

= 49 × 2 Perform operations inside parentheses.

= 98 Multiply.

= 98

Question 17.

17 + 15 ÷ 3 – 2^{4}

Answer:

Solution to this example is given below

17 + 15 ÷ 3 – 2^{4}

17 + 15 ÷ 3 – 2^{4} = 17 + 15 ÷ 3 – 16 Evaluate 2^{4}.

= 17 + 5 – 16 Divide.

= 22 – 16 Add.

= 6 Subtract.

= 6

Question 18.

(8 + 56) ÷ 4 – 3^{2}

Answer:

Solution to this example is given below

(8 + 56) ÷ 4 – 3^{2}

(8 + 56) ÷ 4 – 3^{2} = (8 + 56) ÷ 4 – 9 Evaluate 3^{2}.

= 64 ÷ 4 – 9 Perform operations inside parentheses.

= 16 – 9 Divide.

= 7 Subtract.

= 7

Question 19.

The nature park has a pride of 7 adult lions and 4 cubs. The adults eat 6 pounds of meat each day and the cubs eat 3 pounds. Simplify 7 × 6 + 4 × 3 to find the amount of meat consumed each day by the lions.

Answer:

Solution to this example ¡s given below 7 × 6 + 4 × 3

7 × 6 + 4 × 3 = 7 × 6 + 12 Multiply.

= 42 + 12 Multiply.

= 54 Add.

= 1

Each day by the lions is equal to 54 pounds.

**Essential Question**

Question 20.

How do you use numerical expressions to solve real-world problems?

Answer:

Most real world problems can be converted to algebraic expressions and equations to solve them. For example if a person earns a fixed monthly salary of $x and has expenses a, b and c, then the expenses can be added to evaluate the total expenses of the month and this sum can be subtracted front the amount of monthly salary to evaluate monthly savings and so on.

**Texas Go Math Grade 6 Module 10 Mixed Review Texas Test Prep Answer Key**

**Selected Response**

Question 1.

Which expression has a value that is less than the base of that expression?

(A) 2^{3}

(B) \(\left(\frac{5}{6}\right)^{2}\)

(C) 3^{2}

(D) 4^{4}

Answer:

(B) \(\left(\frac{5}{6}\right)^{2}\)

Explaination:

Identify the expression which has a value of less than the basa

(A) The base is 2 and the exponent is 3.

= 2 × 2 × 2 multiply the base three times

= 8

8 is not less than 2

(B) The base is 2 and the exponent is 3.

= \(\frac{5}{6} \times \frac{5}{6}\) multiply the base twice

= \(\frac{25}{36}\)

\(\frac{25}{36}\) is less than \(\frac{5}{6}\)

(C) The base is 3 and the exponent is 2.

= 3 × 3 multiply the base twice

= 9

9 is not less than 3

(D) The base is 2 and the exponent is 3.

= 4 × 4 × 4 × 4 multiply the base tour times

= 256

256 is not less than 4

The expression with a value less than the base is B. \(\left(\frac{5}{6}\right)^{2}\) because the base is a fraction.

Question 2.

After the game the coach bought 9 chicken meals for $5 each and 15 burger meals for $6 each. What percent of the total amount the coach spent was used for the chicken meals?

(A) 33\(\frac{1}{3}\)%

(B) 45%

(C) 66\(\frac{2}{3}\)%

(D) 90%

Answer:

(A) 33\(\frac{1}{3}\)%

Explaination:

Solution to this example is given below

9 × 5 + 15 × 6

9 × 5 + 15 × 6 = 9 × 5 + 90 Multiply.

= 45 + 90 Multiply.

= 135 Add.

We now calculate the percentage

Percent = \(\frac{45}{135}\) × 100%

= \(\frac{4500}{135}\)

= 33\(\frac{1}{3}\)%

Question 3.

Which operation should you perform first when you simplify 75 – (8 + 45 ÷ 3) × 7?

(A) addition

(B) division

(C) multiplication

(D) subtraction

Answer:

(B) division

Explaination:

Solution to this example is given below

175 – (8 + 45 ÷ 3) × 7

175 – (8 + 45 ÷ 3) × 7 = 175 – (8 + 15) × 7 [Divide.]

= 175 – 23 × 7 [Perform operations inside parentheses.]

= 175 – 161 [Multiply.]

= 14 [Subtract.]

B is the correct option

Division is first operation

Question 4.

At Tanika’s school, three people are chosen in the first round. Each of those people chooses 3 people in the second round, and so on. How many people are chosen in the sixth round?

(A) 18

(B) 216

(C) 243

(D) 729

Answer:

(D) 729

Explaination:

First round = 3^{1} = 3

Second round = 3^{2} = 9

Third round = 3^{3} = 27

Fourth round = 3^{4} = 81

Fifth round = 3^{5} = 243

Sixth round = 3^{6} = 729

There are 729 people chosen in the sixth round.

Question 5.

Which expression shows the prime factorization of 100?

(A) 2^{2} × 5^{2}

(B) 10 × 10

(C) 10^{10}

(D) 2 × 5 × 10

Answer:

(A) 2^{2} × 5^{2}

Explaination:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 100 are 2, 2, 5 and 5

The prime factorization of 100 is 2 × 2 × 5 × 5 or 2^{2} × 5^{2}

Question 6.

Which number has only two factors?

(A) 21

(B) 23

(C) 25

(D) 27

Answer:

(B) 23

Explaination:

Let’s check which number has two factors

(A) List the factors of 21

21 = 1 × 21

21 = 3 × 7

Option A is not correct answer

(B) List the factor of 23

23 = 1 × 23

Option B is correct answer

(C) List the factors of 25

25 = 1 × 25

25 = 5 × 5

Option C is not correct answer

(D) List the factors of 27

27 = 1 × 27

27 = 3 × 9

Option D is not correct answer

Question 7.

Which expression is equivalent to 3.6 × 3.6 × 3.6 × 3.6?

(A) 3.6 × 4

(B) 36^{3}

(C) 3^{4} × 6^{4}

(D) 3.6^{4}

Answer:

(D) 3.6^{4}

Explaination:

Solution to this example is given below

3.6 × 3.6 × 3.6 × 3.6

Find the base, or the numbers being multiplied. The base is 3.6

Find the exponent by counting the number of the 3.6s being multiplied.

The exponent is 4

Question 8.

Which expression gives the prime factorization of 80?

(A) 2^{4} × 10

(B) 2 × 5 × 8

(C) 2^{3} × 5

(D) 2^{4} × 5

Answer:

(D) 2^{4} × 5

Explaination:

The prime factorization of a number is the number written as the product of its prime factors. For example, the prime factors of 80 are 2, 2, 2, 2 and 5.

The prime factorization of 80 is 2 × 2 × 2 × 2 × 5 or 2^{4} × 5

**Gridded Response**

Question 9.

Alison raised 10 to the 5th power. Then she divided this value by 100. What was the quotient?

Answer:

Evaluate the expression.

= 10^{5} ÷ 100 [evaluate the exponent]

= 100,000 ÷ 100 [divide the numbers]

= 1,000

The answer on the grid must be 1,000.