Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 17.3 Customary and Metric Units of Temperature to secure good marks & knowledge in the exams.
McGraw-Hill Math Grade 8 Answer Key Lesson 17.3 Customary and Metric Units of Temperature
Exercises
CONVERT
Question 1.
150° C = ______________ F
Answer:
302° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 150°c, 150 x (\(\frac{9}{5}\)) + 32 = F,
\(\frac{1350}{5}\) + 32 = F, 270 + 32 = F,
F = 302°, So 150° C = 302 ° F.
Question 2.
150° F = ______________ C
Answer:
65.6° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 150°F, (150 – 32) x (\(\frac{5}{9}\)) = C,
118 x \(\frac{5}{9}\) = C, \(\frac{590}{9}\) = C,
C = 65.6°, So 150° F = 65.6° C.
Question 3.
0° C = _______________ F
Answer:
32° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C = 0° C, 0 x (\(\frac{9}{5}\)) + 32 = F,
32° = F, So 0° C = 32° F.
Question 4.
0° F = ____________ C
Answer:
-17.8° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 0° F, (0 – 32) x (\(\frac{5}{9}\)) = C,
-32 x \(\frac{5}{9}\) = C, \(\frac{-160}{9}\) = C,
C = -17.8 ° F, So 0° F = -17.8° C.
Question 5.
216° F = _____________ C
Answer:
102.2° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 216° F, (216 – 32) x (\(\frac{5}{9}\)) = C,
184 x \(\frac{5}{9}\) = C, \(\frac{920}{9}\) = C,
C = 102.2° F, So 216° F = 102.2° C.
Question 6.
105° C = ______________ F
Answer:
221° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 105° C, 105 x (\(\frac{9}{5}\)) + 32 = F,
\(\frac{945}{5}\) + 32 = F, 189° + 32° = F,
221° = F, So 105° C = 221° F.
Question 7.
72° F = _____________ C
Answer:
22.2° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 72° F, (72 – 32) x (\(\frac{5}{9}\)) = C,
40 x \(\frac{5}{9}\) = C, \(\frac{200}{9}\) = C,
C = 22.2°, So 72° F = 22.2° C.
Question 8.
30° C = ______________ F
Answer:
86° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 30° C, 30 x (\(\frac{9}{5}\)) + 32 = F,
\(\frac{270}{5}\) + 32 = F, 54° + 32° = F,
86° = F, So 30° C = 86° F.
Question 9.
-25° F = ______________ C
Answer:
-31.7° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = -25° F, (-25 – 32) x (\(\frac{5}{9}\)) = C,
57 x \(\frac{5}{9}\) = C, \(\frac{285}{9}\) = C,
C = -31.7°, So -25° F = -31.7° C.
Question 10.
35° F = _____________ C
Answer:
1.7° C,
Explanation:
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 35° F, (35 – 32) x (\(\frac{5}{9}\)) = C,
3 x \(\frac{5}{9}\) = C, \(\frac{15}{9}\) = C,
C = 1.666666°, So 35° F = 1.7° C.
Question 11.
37° C = _____________ F
Answer:
98.6° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 37°C, 37 x (\(\frac{9}{5}\)) + 32 = F,
\(\frac{333}{5}\) + 32 = F, 66.6° + 32° = F,
98.6° = F, So 30° C = 89.6° F.
Question 12.
950° C = _____________ F
Answer:
1742° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 30° C, 950 x (\(\frac{9}{5}\)) + 32 = F,
\(\frac{8550}{5}\) + 32 = F, 1710° + 32° = F,
1742° = F, 30° C = 1742° F.
Question 13.
The melting point of aluminum is 1,219° F and the melting point of nickel is 2,646° F. What is the temperature difference between the two melting points? Express your answer in degrees Celsius.
Answer:
The temperature difference between the two melting points is 775° C,
Explanation:
The melting point of aluminum is 1,219° F and
the melting point of nickel is 2,646° F.
The temperature difference between the
two melting points is 2646 – 1219 = 1427° F.
To convert ° F to ° C, (F – 32) x (\(\frac{5}{9}\)) = C,
Given F = 1,427° F, (1427 – 32) x (\(\frac{5}{9}\)) = C,
1395 x \(\frac{5}{9}\) = C, \(\frac{6975}{9}\) = C,
C = 775°, 1427° F = 775° C.
Question 14.
Jamie took his temperature with a Celsius thermometer, and it read 38° C. What would his temperature be in degrees Fahrenheit?
Answer:
The temperature is 100.4° F,
Explanation:
To convert ° C to ° F, C x (\(\frac{9}{5}\)) + 32 = F,
Given C= 38° C, 38 X (\(\frac{9}{5}\)) + 32 = F,
\(\frac{342}{5}\) + 32 = F, 68.4° + 32° = F,
100.4° = F, 38° C = 100.4° F.