Practice the questions of **McGraw Hill Math Grade 4 Answer Key PDF Chapter 11 Lesson 7 Using Line Plots to Solve Problems **to secure good marks & knowledge in the exams.

## McGraw-Hill Math Grade 4 Answer Key Chapter 11 Lesson 7 Using Line Plots to Solve Problems

**Solve**

The line plot shows the height in feet of a number of parade balloons.

Question 1.

What is the difference between the tallest balloon and the shortest balloon shown on the line plot?

Answer:

4\(\frac{1}{4}\)

Explanation:

The above line plot tells that the tallest balloon is 49\(\frac{3}{4}\) fee

The shortest balloon is 45\(\frac{2}{4}\) feet

Subtract to find the difference

49\(\frac{3}{4}\) – 45\(\frac{2}{4}\) = 4\(\frac{1}{4}\) feet

So, the difference between tallest balloon and the shortest balloon shown on the line plot is 4\(\frac{1}{4}\) feet.

Question 2.

What is the difference of the most common height shown and the shortest height shown?

Answer:

2 feet

Explanation:

The above line plot tells that the height of the most common balloon is 47\(\frac{2}{4}\)

The height of the shortest balloon is 45\(\frac{2}{4}\)

Subtract to find the difference

47\(\frac{2}{4}\) – 45\(\frac{2}{4}\) = 2

So, the difference of the most common height shown and the shortest height is 2 feet.