Refer to our Texas Go Math Grade 7 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations.

## Texas Go Math Grade 7 Module 6 Answer Key Theoretical Probability and Simulations

**Texas Go Math Grade 7 Module 6 Are You Ready? Answer Key**

**Write each fraction as a decimal and a percent.**

Question 1.

\(\frac{3}{4}\) ____________

Answer:

Divide 3 by 4. Write a decimal point and insert extra zeros in the dividend.

The result is 0.75.

Move the decimal point two places to the right and add the “%” sign.

0.75 = 75%

\(\frac{3}{4}\) = 75%

Question 2.

\(\frac{2}{5}\) ____________

Answer:

Divide 2 by 5. Write a decimal point and insert extra zeros in the dividend.

The result is 0.40.

Move the decimal point two places to the right and add the “%” sign.

0.40 = 40%

\(\frac{2}{5}\) = 40%

Question 3.

\(\frac{9}{10}\) ____________

Answer:

Divide 9 by 10. Write a decimal point and insert extra zeros in the dividend.

The result is 0.90.

Move the decimal point two places to the right and add the “%” sign.

0.90 = 90%

\(\frac{9}{10}\) = 90%

Question 4.

\(\frac{7}{20}\) ____________

Answer:

Divide 7 by 20. Write a decimal point and insert extra zeros in the dividend.

The result is 0.35.

Move the decimal point two places to the right and add the “%” sign.

0.35 = 35%

\(\frac{7}{20}\) = 35%

Question 5.

\(\frac{7}{8}\) ____________

Answer:

Divide 7 by 8. Write a decimal point and insert extra zeros in the dividend.

The result is 0.875.

Move the decimal point two places to the right and add the “%” sign.

0.875 = 87.5%

\(\frac{7}{8}\) = 87.5%

Question 6.

\(\frac{1}{20}\) ____________

Answer:

Divide 1 by 20. Write a decimal point and insert extra zeros in the dividend.

The result is 0.05.

Move the decimal point two places to the right and add the “%” sign.

0.05 = 5%

\(\frac{1}{20}\) = 5%

Question 7.

\(\frac{19}{25}\) ____________

Answer:

Divide 19 by 25. Write a decimal point and insert extra zeros in the dividend.

The result is 0.76.

Move the decimal point two places to the right and add the “%” sign.

0.76 = 76%

\(\frac{19}{25}\) = 76%

Question 8.

\(\frac{23}{50}\) ____________

Answer:

Divide 23 by 50. Write a decimal point and insert extra zeros in the dividend.

The result is 0.46.

Move the decimal point two places to the right and add the “%” sign.

0.46 = 46%

\(\frac{23}{50}\) = 46%

**Find each difference.**

Question 9.

1 – \(\frac{1}{5}\) ___________

Answer:

1 – \(\frac{1}{5}\) = \(\frac{5}{5}\) – \(\frac{1}{5}\) Write 1 as \(\frac{5}{5}\).

= \(\frac{5-1}{5}\) Subtract the numerators.

= \(\frac{4}{5}\)

Question 10.

1 – \(\frac{2}{9}\) ___________

Answer:

1 – \(\frac{2}{9}\) = \(\frac{9}{9}\) – \(\frac{2}{9}\) Write 1 as \(\frac{9}{9}\).

= \(\frac{9-2}{9}\) Subtract the numerators.

= \(\frac{7}{9}\)

Question 11.

1 – \(\frac{8}{13}\) ___________

Answer:

1 – \(\frac{8}{13}\) = \(\frac{13}{13}\) – \(\frac{8}{13}\) Write 1 as \(\frac{13}{13}\).

= \(\frac{13-8}{13}\) Subtract the numerators.

= \(\frac{5}{13}\)

Question 12.

1 – \(\frac{3}{20}\) ___________

Answer:

1 – \(\frac{3}{20}\) = \(\frac{20}{20}\) – \(\frac{3}{20}\) Write 1 as \(\frac{20}{20}\).

= \(\frac{20-3}{20}\) Subtract the numerators.

= \(\frac{17}{20}\)

**Multiply. Write each product in simplest form.**

Question 13.

\(\frac{8}{15}\) × \(\frac{5}{8}\) ___________

Answer:

\(\frac{8}{15}\) × \(\frac{5}{8}\) = \(\frac{8}{15}\) × \(\frac{5}{8}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{3}\) × \(\frac{1}{1}\)

= \(\frac{1 \cdot 1}{3 \cdot 1}\)

= \(\frac{1}{3}\)

Question 14.

\(\frac{2}{9}\) × \(\frac{3}{4}\) ___________

Answer:

\(\frac{2}{9}\) × \(\frac{3}{4}\) = \(\frac{2}{9}\) × \(\frac{3}{4}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{3}\) × \(\frac{1}{2}\)

= \(\frac{1 \cdot 1}{3 \cdot 2}\)

= \(\frac{1}{6}\)

Question 15.

\(\frac{9}{16}\) × \(\frac{12}{13}\) ___________

Answer:

\(\frac{9}{16}\) × \(\frac{12}{13}\) = \(\frac{9}{16}\) × \(\frac{12}{13}\) Divide numerators and denominators by the common factors.

= \(\frac{9}{4}\) × \(\frac{3}{13}\)

= \(\frac{9 \cdot 3}{4 \cdot 13}\)

= \(\frac{27}{52}\)

Question 16.

\(\frac{7}{10}\) × \(\frac{5}{28}\) ___________

Answer:

\(\frac{7}{10}\) × \(\frac{5}{28}\) = \(\frac{7}{10}\) × \(\frac{5}{28}\) Divide numerators and denominators by the common factors.

= \(\frac{1}{2}\) × \(\frac{1}{4}\)

= \(\frac{1 \cdot 1}{2 \cdot 4}\)

= \(\frac{1}{8}\)

**Texas Go Math Grade 7 Module 6 Reading Start-Up Answer Key**

**Visualize Vocabulary**

Use the ✓ words to complete the graphic.

**Understand Vocabulary**

Match the term on the left to the correct expression on the right.

Answer:

1. Compound event – an event made of two or more simple events.

2. Theoretical probability – the ratio of the number of equally likely outcomes in an event to the total number of possible outcomes.

3. Complement – the set of all outcomes that are not the desired event.

**Active Reading**

Two-Panel Flip Chart Create a two-panel flip chart, to help you understand the concepts in this module. Label one flap “Simple Events and the other flap “Compound Events’ As you study each lesson, write important ideas under the appropriate flap. Include information that will help you remember the concepts later when you look back at your notes.