Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 15.2 Customary Units of Liquid Volume to secure good marks & knowledge in the exams.
McGraw-Hill Math Grade 8 Answer Key Lesson 15.2 Customary Units of Liquid Volume
Exercises
CONVERT
Question 1.
72 c = ___________ qt
Answer:
18 qt,
Explanation:
As 1 cup = 0.25 quart, So 72 c = 18 qt.
Question 2.
12 qt = ____________ c
Answer:
48 c,
Explanation:
As 1 qt = 4 cups, So 12 qt = 48 c.
Question 3.
3 qt 1 pt = ____________ c
Answer:
5.99605 c,
Explanation:
As 1 qt = 1.66535 pt, So 3 qt = 4.99605 pt,
Therefore 3 qt 1 pt = 4.99605 pt + 1 pt = 5.99605 c.
Question 4.
192 gal = _____________ qt
Answer:
922.3296 qt,
Explanation:
As 1 gal = 4.8038 qt, So 192 gal = 192 X 4.8038 = 922.3296 qt.
Question 5.
328 qt = ____________ gal
Answer:
82 gal,
Explanation:
As 1 qt = 0.25 gal, So 328 qt = 82 gal.
Question 6.
2 gal 1 qt = _______________ c
Answer:
10.6076 c,
Explanation:
As 1 gal = 4.8038 qt, So 2 gal = 9.6076,
Therefore 2 gal 1 qt = 9.6076 + 1 = 10.6076 c.
Question 7.
6 qt 1 c = ____________ c
Answer:
25 c,
Explanation:
As 1 qt = 4 c, So 6 qt = 24 c,
Therefore 6 qt 1 c = 24 c + 1 c = 25 c.
Question 8.
52 c = _____________ qt
Answer:
13 qt,
Explanation:
As 1 c = 0.25 qt, So 52 c = 13 qt.
Question 9.
\(\frac{3}{4}\) gal = _____________ c
Answer:
12 c,
Explanation:
As 1 gal = 16 c, So \(\frac{3}{4}\) gal = 12 c.
Question 10.
66 pt = _______________ gal
Answer:
9.907854 gal,
Explanation:
As 1 pt = 0.150119 gal,
So 66 pt = 66 X 0.150119 = 9.907854 gal.
Question 11.
4 qt 1 c = _____________ c
Answer:
17 c,
Explanation:
As 1 qt = 4 c, So 4 qt = 16 c,
Therefore 4 qt 1 c = 16 c + 1 c = 17 c.
Question 12.
7\(\frac{1}{2}\) qt = _____________ gal = ___________ C
Answer:
1.875 gal, 30 c,
Explanation:
As 1 qt = 0.25 gal, So 7\(\frac{1}{2}\) qt = \(\frac{15}{2}\) qt = 1.875 gal. As 1 qt = 4 c,
So 7\(\frac{1}{2}\) qt = \(\frac{15}{2}\) qt =
7.5 X 4 = 30 c.
Question 13.
35 qt 3 c = ____________ gal
Answer:
9 gal,
Explanation:
As 1 qt = 4 c, So 35 qt = 140 c,
Therefore 35 qt 3 c = 140 c + 4 c = 144 c,
As we know 35 qt 3 c is 144 c, As 1 c = 0.0625 gal, So 144 c = 9 gal.
Question 14.
256 c = _______________ gal
Answer:
16 gal,
Explanation:
As 1 c = 0.0625 gal, So 256 c = 16 gal.
Question 15.
132 c = ___________ pt = ___________ qt
Answer:
4461.6 pt, 33 qt,
Explanation:
As 1 c = 33.8 pt, So 132 c = 4461.6 pt,
As 1 c = 0.25 qt, So 132 c = 33 qt.
Question 16.
34 gal 1 qt = ____________ pt
Answer:
273.6656 pt,
Explanation:
As 1 gal = 4.8038 qt, So 34 gal = 163.3292 qt,
Therefore 34 gal 1 qt = 163.3292 qt + 1 qt = 164.3292 qt
As we know 1 qt = 1.66535 pt, So 164.3292 qt = 273.6656.
Question 17.
Allison’s aquarium holds 25 gallons of water. One quart of water evaporated from the aquarium. How much water is left in the aquarium?
Answer:
119.095 quarts is left in the aquarium,
Explanation:
Given Allison’s aquarium holds 25 gallons of water.
One quart of water evaporated from the aquarium.
So water is left in the aquarium is as 1 gallon = 4.8038 quart,
25 gallons = 25 X 4.8038 quart = 120.095 quarts,
120.095 quarts – 1 quarts = 119.095 quarts.
Question 18.
Bobby drinks 1 quart and 1 cup of water for every 3 miles he runs. If he runs 9 miles, how much water should he drink?
Answer:
Bobby should drink 15 cups of water if he runs 9 miles,
Explanation:
Given Bobby drinks 1 quart and 1 cup of water for
every 3 miles he runs. As 1 quart = 4 cups, so
for 3 miles Bobby drinks 4 cups + 1 cup = 5 cups, So 1 mile it is 5/3 cups, therefore for 9 miles water should he drink is 5 X 9/3 = 15 cups.