Practice the questions of **McGraw Hill Math Grade 8 Answer Key PDF Lesson 15.1 Customary Units of Length **to secure good marks & knowledge in the exams.

## McGraw-Hill Math Grade 8 Answer Key Lesson 15.1 Customary Units of Length

**Exercises**

**CONVERT**

Question 1.

72 in. = ____________ ft

Answer:

5.999976 ft,

Explanation:

As 1 inch = 0.083333 ft, So 72 in = 72 X 0.083333 = 5.999976 ft.

Question 2.

12 ft = _____________ in.

Answer:

144 in,

Explanation:

As 1 feet = 12 inches, So 12 ft = 12 X 12 = 144 inches,

Question 3.

3 ft 8 in. = ____________ in.

Answer:

44 inches,

Explanation:

As 1 ft = 12 inches, So 3 ft 8 in. = 3ft X 12 + 8 in. = 44 in.

Question 4.

192 in. = _______________ ft

Answer:

0.015999936 ft,

Explanation:

As 1 inch = 0.083333 ft, So 192 in. = 192 X 0.083333 = 0.015999936 ft.

Question 5.

7,920 ft = ______________ mi

Answer:

1.38068226 mi,

Explanation:

As 1ft = 0.000189394 mi, So 7,920 ft = 7,920 X 0.000189394 =

1.38068226 mi.

Question 6.

16 ft 6 in. = _______________ yd

Answer:

5.5 yd,

Explanation:

As 1 ft = 12 inches,

So 16 ft 6 in. = 16 ft X 12 + 6 = 198 in. 198 inches in yd,

As we know 1 in. = 0.0277778 yd, 198 inches = 198 X 0.0277778 = 5.5 yd.

Question 7.

4 ft 9 in. = ______________ in.

Answer:

57 in,

Explanation:

As 1 ft = 12 inches, So 4 ft 9 in. = 4ft X 12 + 9 = 57 in.

Question 8.

1056 ft = ______________ mi

Answer:

0.2 mi,

Explanation:

As 1ft = 0.000189394 mi, So 1056 ft. = 1056 X 0.000189394 = 0.2 mi.

Question 9.

\(\frac{4}{5}\)mi = ____________ in.

Answer:

50,688 in,

Explanation:

As 1 mi = 63,360 in, So \(\frac{4}{5}\)mi =

\(\frac{4}{5}\)mi X 63,360 = 50,688 in.

Question 10.

66 in. = _______________ ft

Answer:

5.499978 ft,

Explanation:

As 1 inches = 0.083333 ft, So 66 in. = 66 in. X 0.083333 ft = 5.499978 ft.

Question 11.

648 in. = _____________ yd

Answer:

18 yd,

Explanation:

As 1 inches = 0.0277778 yd, So 648 in. = 648 in. X 0.0277778 yd = 18 yd.

Question 12.

7\(\frac{1}{2}\) yd = ____________ ft = __________ in.

Answer:

270 inches,

Explanation:

As 1 yd = 3 feet,

So 7\(\frac{1}{2}\)mi = \(\frac{15}{2}\)mi X 3 = 22.5 ft.

Now 1 ft = 12 inches, So 22.5 ft = 22.5 X 12 inches = 270 inches.

Question 13.

35 ft = ____________ yd

Answer:

11.666655 yd,

Explanation:

As 1ft = 0.333333 yd, So 35ft. = 35 ft X 0.333333 yd =11.666655 yd.

Question 14.

16 yd 2 ft = ____________ in.

Answer:

600 in,

Explanation:

As 1 yd = 3 ft, So 16 yd 2 ft = 16 yd X 3 + 2 = 50 ft,

50 ft in inches, As we know 1 ft = 12, So 50 ft = 50 ft X 12 = 600 in.

Question 15.

2 mi 303 yd = _______________ ft

Answer:

11,469 ft,

Explanation:

As 1 mi = 1,760 yd,

So 2 mi 303 yd = 2 X 1760 + 303 = 3,823 yd, 3,823 yd in ft,

As we know 1 yd = 3 ft, So 3,823 yd = 3,823 yd X 3 ft = 11,469 ft.

Question 16.

34 yd 2 ft = _____________ in.

Answer:

1,248 in,

Explanation:

As 1 yd = 3 ft, So 34 yd 2 ft = 34 X 3 + 2 = 104 ft,

104 ft in inches, As we know 1 ft = 12 inches,

So 104 ft = 104 X 12 = 1,248 in.

Question 17.

The river is 768 yards wide where the city plans to build a new bridge. How many 32-foot sections of bridge will the city engineers need in order to build the bridge?

Answer:

72 sections of 32 foot,

Explanation:

Given the river is 768 yards wide where the city plans to

build a new bridge. So 32-foot sections of bridge will the

city engineers need in order to build the bridge is as 1 yard = 3 feet,

so 768 yards = 768 X 3 feet = 2,304 feet, Therefore 32 foot sections are

2,304 feet ÷ 32 feet = 72 sections.

Question 18.

Patty wants to know how far she can throw a softball. After throwing, she estimates that the ball traveled 1,764 inches.

How many yards is that? ______________

How many feet? _______________

Answer:

The ball traveled 49 yd,

In feet the ball traveled 146.9999412 ft = 147 ft,

Explanation:

As 1 inch = 0.0277778 yd,

So 1,764 inches = 1764 X 0.0277778 yd = 49 yd.

As 1 inch = 0.0833333 ft, So 1,764 inches = 1,764 X 0.0833333 ft =

146.9999412 ft ≈ 147 ft.