McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing

Practice the questions of McGraw Hill Math Grade 8 Answer Key PDF Lesson 14.3 Solve Equations by Graphing to secure good marks & knowledge in the exams.

McGraw-Hill Math Grade 8 Answer Key Lesson 14.3 Solve Equations by Graphing

Exercises

GRAPH

Determine the point of Intersection of the two lines.

Question 1.
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 1
y = x + 3
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
y = 2x + 1
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
Answer:
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing-1

Explanation:
Determined the point of Intersection of the given two lines
1. y = x + 3, 2. y = 2x + 1,
1. y = x + 3, if x = -2, y =  -2 + 3 = 1,
if x = -1, y = -1 + 3 = 2, if x = 0, y = 0 + 3 = 3,
if x = 1, y = 1 + 3 = 4, if x = 2, y = 2 + 3 = 5,
if x = 3, y = 3 + 3 = 6.
2. y = 2x + 1, if x = -2, y =  2 X -2  + 1 = -4 + 1 = -3,
if x = -1, y = 2 X -1 + 1 = -2 + 1 = -1,
if x = 0, y = 2 X 0 + 1 = 0 + 1 = 1,
if x = 1, y = 2 X 1 + 1 = 2 + 1 = 3,
if x = 2, y = 2 X 2 + 1 = 4 + 1 = 5,
if x = 3, y = 2 X 3 + 1 = 6 + 1 = 7 as (2,5) as shown above.

Question 2.
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 1
y = x – 4
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
y = -x + 2
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
Answer:
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing-2

Explanation:
Determined the point of Intersection of the given two lines
1. y = x – 4, 2. y = -x + 2,
1. y = x – 4, if x = -2, y =  -2 – 4 = -6, if x = -1, y = -1 – 4 = -5,
if x = 0, y = 0 – 4 = -4, if x = 1, y = 1 – 4 = -3,
if x = 2, y = 2 – 4 = -2, if x = 3, y = 3 – 4 = -1.
2. y =  -x + 2,
if x = -2, y =  -(-2) + 2 = 4, if x = -1, y = -(-1) + 2 = 3,
if x = 0, y = -0 + 2 = 2, if x = 1, y = -(1) + 2 = 1,
if x = 2, y = -(2) + 2 = 0, if x = 3, y = -(3) + 2 = -1
as (3,-1) as shown above.

Question 3.
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 1
y = 4x – 3
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
y = x
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing 2
Answer:
McGraw Hill Math Grade 8 Lesson 14.3 Answer Key Solve Equations by Graphing-3

Explanation:
Determined the point of Intersection of the given two lines
1. y = 4x – 3, 2. y = x,
1. y = 4x – 3, if x = -2, y =  4 X -2 – 3 = -11,
if x = -1, y = 4 X -1 – 3 = -7, if x = 0, y = 4 X 0 – 3 = -3,
if x = 1, y = 4 X 1 – 3 = 1, if x = 2, y = 4 X 2  – 3 = 5,
if x = 3, y = 4 X 3 – 3 = 9.
2. y = x, if x = -2, y = -2,
if x = -1, y = -1, if x = 0, y = 0,
if x = 1, y = 1, if x = 2, y = 2,
if x = 3, y = 3 as (1,1) as shown above.

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