Practice questions available in **McGraw Hill Math Grade 6 Answer Key PDF Lesson 7.1 Multiplying Fractions and Whole Numbers** will engage students and is a great way of informal assessment.

## McGraw-Hill Math Grade 6 Answer Key Lesson 7.1 Multiplying Fractions and Whole Numbers

**Exercises Estimate**

Question 1.

5 × \(\frac{3}{4}\)

Answer:

5 × \(\frac{3}{4}\) = 3\(\frac{3}{4}\)

Explanation:

5 × \(\frac{3}{4}\)

= \(\frac{15}{4}\)

= 3\(\frac{3}{4}\)

Question 2.

4 × \(\frac{2}{7}\)

Answer:

4 × \(\frac{2}{7}\) = 1\(\frac{1}{7}\)

Explanation:

4 × \(\frac{2}{7}\)

= \(\frac{8}{7}\)

= 1\(\frac{1}{7}\)

Question 3.

21 × \(\frac{5}{8}\)

Answer:

21 × \(\frac{5}{8}\) = 13\(\frac{1}{8}\)

Explanation:

21 × \(\frac{5}{8}\)

= \(\frac{105}{8}\)

= 13\(\frac{1}{8}\)

Question 4.

11 × \(\frac{2}{9}\)

Answer:

11 × \(\frac{2}{9}\) = 2\(\frac{4}{9}\)

Explanation:

11 × \(\frac{2}{9}\)

= \(\frac{22}{9}\)

= 2\(\frac{4}{9}\)

Question 5.

4 × \(\frac{3}{11}\)

Answer:

4 × \(\frac{3}{11}\) = 1\(\frac{1}{11}\)

Explanation:

4 × \(\frac{3}{11}\)

= \(\frac{12}{11}\)

= 1\(\frac{1}{11}\)

Question 6.

13 × \(\frac{13}{14}\)

Answer:

13 × \(\frac{13}{14}\) = 12\(\frac{1}{14}\)

Explanation:

13 × \(\frac{13}{14}\)

= \(\frac{169}{14}\)

= 12\(\frac{1}{14}\)

Question 7.

21 × \(\frac{10}{23}\)

Answer:

21 × \(\frac{10}{23}\) = 9 \(\frac{3}{23}\)

Explanation:

21 × \(\frac{10}{23}\)

= \(\frac{210}{23}\)

= 9 \(\frac{3}{23}\)

Question 8.

7 × \(\frac{2}{3}\)

Answer:

7 × \(\frac{2}{3}\) = 4 \(\frac{2}{3}\)

Explanation:

7 × \(\frac{2}{3}\)

= \(\frac{14}{3}\)

= 4 \(\frac{2}{3}\)

Question 9.

12 × \(\frac{7}{19}\)

Answer:

12 × \(\frac{7}{19}\) = 4\(\frac{8}{19}\)

Explanation:

12 × \(\frac{7}{19}\)

= \(\frac{84}{19}\)

= 4\(\frac{8}{19}\)

Question 10.

14 × \(\frac{3}{5}\)

Answer:

14 × \(\frac{3}{5}\) = 8\(\frac{2}{5}\)

Explanation:

14 × \(\frac{3}{5}\)

=\(\frac{42}{5}\)

= 8\(\frac{2}{5}\)

Question 11.

14 × \(\frac{11}{13}\)

Answer:

14 × \(\frac{11}{13}\) = 11\(\frac{11}{13}\)

Explanation:

14 × \(\frac{11}{13}\)

= \(\frac{154}{13}\)

= 11\(\frac{11}{13}\)

Question 12.

13 × \(\frac{4}{17}\)

Answer:

13 × \(\frac{4}{17}\) = 3\(\frac{1}{17}\)

Explanation:

13 × \(\frac{4}{17}\)

= \(\frac{52}{17}\)

= 3\(\frac{1}{17}\)

Question 13.

10 × \(\frac{9}{23}\)

Answer:

10 × \(\frac{9}{23}\) = 3\(\frac{21}{23}\)

Explanation:

10 × \(\frac{9}{23}\)

= \(\frac{90}{23}\)

= 3\(\frac{21}{23}\)

Question 14.

13 × \(\frac{21}{22}\)

Answer:

13 × \(\frac{21}{22}\) = 12\(\frac{9}{22}\)

Explanation:

13 × \(\frac{21}{22}\)

= \(\frac{273}{22}\)

= 12\(\frac{9}{22}\)

Question 15.

5 × \(\frac{14}{27}\)

Answer:

5 × \(\frac{14}{27}\) = 2\(\frac{16}{27}\)

Explanation:

5 × \(\frac{14}{27}\)

= \(\frac{70}{27}\)

= 2\(\frac{16}{27}\)

Question 16.

Chet found a pair of sunglasses that he would like to buy. They normally cost $43.00, but this week they are on sale for only \(\frac{7}{8}\) of the usual price. How much money will Chet need to buy the sunglasses?

Answer:

Amount of money Chet needs to buy the sunglasses = $37\(\frac{5}{8}\)

Explanation:

Cost of a pair of sunglasses usually = $43.00

Cost of a pair of sunglasses this week on sale for only of the usual price = \(\frac{7}{8}\)

Amount of money Chet needs to buy the sunglasses = Cost of a pair of sunglasses usually × Cost of a pair of sunglasses this week on sale for only of the usual price

= 43 × \(\frac{7}{8}\)

= \(\frac{301}{8}\)

= $37\(\frac{5}{8}\)

Question 17.

Ashlee is riding her bike to the beach. If the beach is 17 miles from her home, and she has already traveled \(\frac{3}{5}\) of the way, how much farther does she have to cycle?

Answer:

Number of miles more she needs to cycle = 10\(\frac{1}{5}\)

Explanation:

Number of miles from her home the beach = 17.

Number of miles already travelled of the way = \(\frac{3}{5}\)

Number of miles more she needs to cycle = Number of miles from her home the beach × Number of miles already travelled of the way

= 17 × \(\frac{3}{5}\)

= \(\frac{51}{5}\)

= 10\(\frac{1}{5}\)