Practice questions available in **McGraw Hill Math Grade 6 Answer Key PDF Lesson 6.2 Changing Mixed Numbers to Improper Fractions** will engage students and is a great way of informal assessment.

## McGraw-Hill Math Grade 6 Answer Key Lesson 6.2 Changing Mixed Numbers to Improper Fractions

**Exercises
Change to Improper Fractions**

Question 1.

2\(\frac{2}{3}\)

Answer:

Improper fraction of 2\(\frac{2}{3}\) = \(\frac{8}{3}\)

Explanation:

2\(\frac{2}{3}\) = [(2 × 3) + 2] ÷ 3

= (6 + 2) ÷ 3

= \(\frac{8}{3}\)

Question 2.

5\(\frac{4}{7}\)

Answer:

Improper fraction of 5\(\frac{4}{7}\) = \(\frac{39}{7}\)

Explanation:

5\(\frac{4}{7}\) = [(5 × 7) + 4)] ÷ 7

= (35 + 4) ÷ 7

= \(\frac{39}{7}\)

Question 3.

21\(\frac{3}{5}\)

Answer:

Improper fraction of 21\(\frac{3}{5}\) = \(\frac{108}{5}\)

Explanation:

21\(\frac{3}{5}\) = [(21 × 5) + 3)] ÷ 5

= (105 + 3) ÷ 5

= \(\frac{108}{5}\)

Question 4.

5\(\frac{3}{8}\)

Answer:

Improper fraction of 5\(\frac{3}{8}\) =

Explanation:

5\(\frac{3}{8}\) = [(5 × 8) + 3] ÷ 8

= (40 + 3) ÷ 8

= \(\frac{43}{8}\)

Question 5.

22\(\frac{6}{7}\)

Answer:

Improper fraction of 22\(\frac{6}{7}\) = \(\frac{160}{7}\)

Explanation:

22\(\frac{6}{7}\) = [(22 × 7) + 6] ÷ 7

= (154 + 6) ÷ 7

= \(\frac{160}{7}\)

Question 6.

15\(\frac{4}{11}\)

Answer:

Improper fraction of 5\(\frac{4}{11}\) = \(\frac{59}{11}\)

Explanation:

5\(\frac{4}{11}\) = [(5 × 11) + 4] ÷ 11

= (55 + 4) ÷ 11

= \(\frac{59}{11}\)

Question 7.

13\(\frac{2}{3}\)

Answer:

Improper fraction of 13\(\frac{2}{3}\) = \(\frac{41}{3}\)

Explanation:

13\(\frac{2}{3}\) = [(13 × 3) + 2] ÷ 3

= (39 + 2) ÷ 3

= \(\frac{41}{3}\)

Question 8.

3\(\frac{11}{17}\)

Answer:

Improper fraction of 3\(\frac{11}{17}\) = \(\frac{62}{17}\)

Explanation:

3\(\frac{11}{17}\) = [(3 × 17) + 11] ÷ 17

= (51 + 11) ÷ 17

= \(\frac{62}{17}\)

Question 9.

2\(\frac{4}{19}\)

Answer:

Improper fraction of 2\(\frac{4}{19}\) = \(\frac{42}{19}\)

Explanation:

2\(\frac{4}{19}\) = [(2 × 19) + 4] ÷ 19

= (38 + 4) ÷ 19

= \(\frac{42}{19}\)

Question 10.

6\(\frac{3}{4}\)

Answer:

Improper fraction of 6\(\frac{3}{4}\) = \(\frac{27}{4}\)

Explanation:

6\(\frac{3}{4}\) = [(6 × 4) + 3] ÷ 4

= (24 + 3) ÷ 4

= \(\frac{27}{4}\)

Question 11.

1\(\frac{1}{51}\)

Answer:

Improper fraction of 1\(\frac{1}{51}\) = \(\frac{52}{51}\)

Explanation:

1\(\frac{1}{51}\) = [(1 × 51) + 1] ÷ 51

= (51 + 1) ÷ 51

= \(\frac{52}{51}\)

Question 12.

55\(\frac{1}{2}\)

Answer:

Improper fraction of 55\(\frac{1}{2}\) = \(\frac{111}{2}\)

Explanation:

55\(\frac{1}{2}\) = [(55 × 2) + 1] ÷ 2

= (110 + 1) ÷ 2

= \(\frac{111}{2}\)

Question 13.

10\(\frac{2}{23}\)

Answer:

Improper fraction of 10\(\frac{2}{23}\) = \(\frac{232}{23}\)

Explanation:

10\(\frac{2}{23}\) = [(10 × 23) + 2] ÷ 23

= (230 + 2) ÷ 23

= \(\frac{232}{23}\)

Question 14.

6\(\frac{4}{7}\)

Answer:

Improper fraction of 6\(\frac{4}{7}\) = \(\frac{46}{7}\)

Explanation:

6\(\frac{4}{7}\) = [(6 × 7) + 4] ÷ 4

= (42 + 4) ÷ 4

= \(\frac{46}{7}\)

Question 15.

13\(\frac{2}{7}\)

Answer:

Improper fraction of 13\(\frac{2}{7}\) = \(\frac{93}{7}\)

Explanation:

13\(\frac{2}{7}\) = [(13 × 7) + 2] ÷ 7

= [91 + 2) ÷ 7

= \(\frac{93}{7}\)

Question 16.

42\(\frac{1}{3}\)

Answer:

Improper fraction of 42\(\frac{1}{3}\) = \(\frac{127}{3}\)

Explanation:

42\(\frac{1}{3}\) = [(42 × 3) + 1] ÷ 3

= (126 + 1) ÷ 3

= \(\frac{127}{3}\)

Question 17.

5\(\frac{1}{19}\)

Answer:

Improper fraction of 5\(\frac{1}{19}\) = \(\frac{96}{19}\)

Explanation:

5\(\frac{1}{19}\) = [(5 × 19) + 1] ÷ 19

= (95 + 1) ÷ 19

= \(\frac{96}{19}\)

Question 18.

12\(\frac{2}{3}\)

Answer:

Improper fraction of 12\(\frac{2}{3}\) = \(\frac{38}{3}\)

Explanation:

12\(\frac{2}{3}\) = [(12 × 3) + 2] ÷ 3

= (36 + 2) ÷ 3

= \(\frac{38}{3}\)

Question 19.

2\(\frac{3}{4}\)

Answer:

Improper fraction of 2\(\frac{3}{4}\) = \(\frac{11}{4}\)

Explanation:

2\(\frac{3}{4}\) = [(2 × 4) + 3] ÷ 4

= (8 + 3) ÷ 4

= \(\frac{11}{4}\)

Question 20.

200\(\frac{33}{100}\)

Answer:

Improper fraction of 200\(\frac{33}{100}\) = \(\frac{20033}{100}\)

Explanation:

200\(\frac{33}{100}\) = [(200 × 100) + 33] ÷ 100

= (20000 + 33) ÷ 100

= \(\frac{20033}{100}\)