Practice questions available in **McGraw Hill Math Grade 6 Answer Key PDF** **Lesson 19.4 Perimeter, Area, and Volume of a Solid: Metric **will engage students and is a great way of informal assessment.

## McGraw-Hill Math Grade 6 Answer Key Lesson 19.4 Perimeter, Area, and Volume of a Solid: Metric

**Exercises
**

**SOLVE**

Question 1.

What is the perimeter of a 5-meter square?

Answer:

Perimeter of the square = 20 m.

Explanation:

Side of the square = 5 m.

Perimeter of the square = 4 × Side of the square

= 4 × 5

= 20 m.

Question 2.

What is the area of a rectangle with sides of 27 km and 1.1 km?

Answer:

Area of a rectangle = 29.7 square km.

Explanation:

Length of the rectangle = 27 km.

Width of the rectangle = 1.1 km.

Area of a rectangle = Length of the rectangle × Width of the rectangle

= 27 × 1.1

= 29.7 square km.

Question 3.

A cube with sides of 2 m has what volume?

Answer:

Volume of a cube = 8 cubic m.

Explanation:

Side of a cube = 2m.

Volume of a cube = Side of a cube × Side of a cube × Side of a cube

= 2 × 2 × 2

= 4 × 2

= 8 cubic m.

Question 4.

A square with sides of 1.2 m has an area of how many sq cm?

Answer:

A square with sides of 1.2 m has an area of 14,400 sq cm.

Explanation:

Side of a square = 1.2 m.

Area of the square = Side of a square × Side of a square

= 1.2 × 1.2

= 1.44 square m.

Conversion:

1 sq m = 10,000 sq cm.

=> 1.44 square m = 1.44 × 10,000

=> 14,400 sq cm.

Question 5.

A cube with sides of 3.6 km has a volume of how many cubic meters?

Answer:

A cube with sides of 3.6 km has a volume of 46,65,60,000 cubic m.

Explanation:

Side of the cube = 3.6 km.

Volume of the cube = Side of the cube × Side of the cube × Side of the cube

= 3.6 × 3.6 × 3.6

= 12.96 × 3.6

= 46.656 cubic km.

Conversion:

1 cubic km = 1000000000 cubic m.

=> 46.656 cubic km = 1,00,00,00,000 × 46.656

=> 46,65,60,000 cubic m.

Question 6.

What is the area of a triangle with a base of 11 m and a height of 18 m?

Answer:

Area of the triangle = 99 square m.

Explanation:

Base of the triangle = 11m.

Height of the triangle = 18m.

Area of the triangle = \(\frac{1}{2}\) × Base of the triangle × Height of the triangle

= \(\frac{1}{2}\) × 11 × 18

= 11 × 9

= 99 square m.

Question 7.

A rectangular prism has a base of 3 m by 10 m and a height of 4 m. What is its volume?

Answer:

Volume of the rectangular prism = 120 cubic m.

Explanation:

Length of the rectangular prism = 10 m.

Width of the rectangular prism = 3m

Height of the rectangular prism = 4m.

Volume of the rectangular prism = Length of the rectangular prism × Width of the rectangular prism × Height of the rectangular prism

= 10 × 3 × 4

= 30 × 4

= 120 cubic m.

Question 8.

What is the volume of air contained in a 500-m-high tent over a field that measures 300 m by 400 m?

Answer:

Volume of the tent = 6,00,00,000 cubic m.

Explanation:

volume of air contained in a 500-m-high tent over a field that measures.

Length of the tent = 400 m.

Width of the tent = 300 m.

Height of the tent = 500 m.

Volume of the tent = Length of the tent × Width of the tent × Height of the tent

= 400 × 300 × 500

= 120000 × 500

= 6,00,00,000 cubic m.

Question 9.

Rita walks 5 km to the east before walking 4 km to the north. She then turns to the west and walks 5 km. How many kilometers will she have to walk to return to her starting point. What was her total distance in meters?

Answer:

Total distance travelled = 18 km.

Explanation:

Number of kilometers Rita walks to the east = 5.

Number of kilometers Rita walks to the north = 4.

Number of kilometers Rita walks to the west = 5.

Number of kilometers Rita walks to the starting point = 4.

Total distance travelled = Number of kilometers Rita walks to the east + Number of kilometers Rita walks to the north + Number of kilometers Rita walks to the west + Number of kilometers Rita walks to the starting point

= 5 + 4 + 5 + 4

= 9 + 5 + 4

= 14 + 4

= 18 km.

Question 10.

Calculate the volume, in cubic meters, of a swimming pool with a level bottom. It is in the shape of a rectangle with sides of 15 m by 9 m, and with a depth of 3 m.

Answer:

volume of the swimming pool = 405 cubic m.

Explanation:

Length of the swimming pool = 15 m.

Width of the swimming pool = 9m.

Height of the swimming pool = 3m.

Volume of the swimming pool = Length of the swimming pool × Width of the swimming pool × Height of the swimming pool

= 15 × 9 × 3

= 135 × 3

= 405 cubic m.

Question 11.

What is the area of a triangle with a base of 10 m and a height of 8 m?

Answer:

Area of a triangle = 40 square m.

Explanation:

Base of the triangle = 10 m.

Height of the triangle = 8 m.

Area of a triangle = \(\frac{1}{2}\) × Base of the triangle × Height of the triangle

= \(\frac{1}{2}\) × 10 × 8

= 5 × 8

= 40 square m.

Question 12.

What is the volume of a rectangular solid that is 2 km by 13 km by 8 km?

Answer:

Volume of the rectangular solid = 208 cubic km.

Explanation:

Length of the rectangular solid = 13 km.

Width of the rectangular solid = 8 km.

Height of the rectangular solid = 2 km.

Volume of the rectangular solid = Length of the rectangular solid × Width of the rectangular solid × Height of the rectangular solid

= 13 × 8 × 2

= 104 × 2

= 208 cubic km.

Question 13.

If you are traveling at 100 kph, how many meters would you travel in 15 minutes?

Answer:

Number of kilometers 15 minutes travelled = 20.

Explanation:

Number of kilometers per hour travelled = 100.

Conversion:

1 hour = 60 minutes.

Number of kilometers 15 minutes travelled = (100 × 15) ÷ 60

= 1500 ÷ 60

= 20.

Question 14.

What is the area of a rectangle with sides of 4 m and 7 m?

Answer:

Area of a rectangle = 28 square m.

Explanation:

Length of the rectangle = 7m.

Width of the rectangle = 4m.

Area of a rectangle = Length of the rectangle × Width of the rectangle

= 7 × 4

= 28 square m.

Question 15.

A carpet store charges by the square meter for carpet, and the store rounds up to the next square meter. How much carpet should be ordered for a room that is 5.5 m by 7.1 m?

Answer:

Area of the carpet = 39.05 square m.

Explanation:

Length of the carpet = 7.1 m.

Width of the carpet = 5.5 m.

Area of the carpet = Length of the carpet × Width of the carpet

= 7.1 × 5.5

= 39.05 square m.

Question 16.

Jim is calculating how much dirt he will have to haul away when he digs a hole for the foundation of a house. He knows that a dump truck can carry 6 cubic meters of dirt at a time. The hole for the house is going to be 10 m by 7 m and 2 m deep. How many truckloads will he be filling?

Answer:

Number of truckloads will he be filling = 23.33.

Explanation:

Number of cubic meters of dirt at a time a dump truck can carry = 6.

Lengths of the hole for the house = 10m, 7m, and 2m.

Volume of the hole for the house = 10m × 7m × 2m

= 70 × 2

= 140 cubic meters .

Conversion:

Number of truckloads will he be filling = Volume of the hole for the house ÷ Number of cubic meters of dirt at a time a dump truck can carry

= 140 ÷ 6

= 23.3.