# McGraw Hill Math Grade 5 Chapter 6 Lesson 8 Answer Key Subtracting Mixed Numbers with Unlike Denominators

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Lesson 8 Subtracting Mixed Numbers with Unlike Denominators are as per the latest syllabus guidelines.

## McGraw-Hill Math Grade 5 Answer Key Chapter 6 Lesson 8 Subtracting Mixed Numbers with Unlike Denominators

Solve

Find equivalent fractions and subtract. Simplify improper fractions.

Question 1.
1$$\frac{1}{4}$$ – $$\frac{1}{6}$$ ______________
1$$\frac{3}{12}$$ – $$\frac{2}{12}$$ = 1$$\frac{1}{12}$$

Question 2.
1$$\frac{2}{3}$$ – $$\frac{1}{2}$$ ______________
1$$\frac{2}{3}$$ – $$\frac{1}{2}$$ = $$\frac{7}{6}$$.

Explanation:
The difference between 1$$\frac{2}{3}$$ – $$\frac{1}{2}$$ is $$\frac{5}{3}$$ – $$\frac{1}{2}$$
= $$\frac{10-3}{6}$$
= $$\frac{7}{6}$$.

Question 3.
1$$\frac{7}{8}$$ – 1$$\frac{3}{6}$$ ______________
1$$\frac{7}{8}$$ – 1$$\frac{3}{6}$$ = $$\frac{3}{8}$$.

Explanation:
The difference between 1$$\frac{7}{8}$$ – 1$$\frac{3}{6}$$ is $$\frac{15}{8}$$ – $$\frac{9}{6}$$
= $$\frac{90-72}{48}$$
= $$\frac{18}{48}$$
= $$\frac{3}{8}$$.

Question 4.

Question 5.
2$$\frac{1}{9}$$ – $$\frac{5}{6}$$ _______________
2$$\frac{1}{9}$$ – $$\frac{5}{6}$$ = $$\frac{23}{18}$$.

Explanation:
The difference between 2$$\frac{1}{9}$$ – $$\frac{5}{6}$$ is $$\frac{19}{9}$$ – $$\frac{5}{6}$$
= $$\frac{114-45}{54}$$
= $$\frac{69}{54}$$
= $$\frac{23}{18}$$.

Question 6.
3$$\frac{1}{2}$$ – 2$$\frac{1}{5}$$ _______________
3$$\frac{1}{2}$$ – 2$$\frac{1}{5}$$ = $$\frac{24}{5}$$.

Explanation:
The difference between 3$$\frac{1}{2}$$ – 2$$\frac{1}{5}$$ is $$\frac{7}{2}$$ – $$\frac{11}{5}$$
= $$\frac{70-22}{10}$$
= $$\frac{48}{10}$$
= $$\frac{24}{5}$$.

Question 7.

3$$\frac{1}{2}$$ – 1$$\frac{3}{7}$$ = $$\frac{29}{14}$$.

Explanation:
The difference between 3$$\frac{1}{2}$$ – 1$$\frac{3}{7}$$ is $$\frac{7}{2}$$ – $$\frac{10}{7}$$
= $$\frac{49-20}{14}$$
= $$\frac{29}{14}$$.

Question 8.

2$$\frac{1}{3}$$ – 1$$\frac{2}{5}$$ = $$\frac{14}{15}$$.

Explanation:
The difference between 2$$\frac{1}{3}$$ – 1$$\frac{2}{5}$$ is $$\frac{7}{3}$$ – $$\frac{7}{5}$$
= $$\frac{35-21}{15}$$
= $$\frac{14}{15}$$.

Question 9.

5$$\frac{6}{7}$$ – 4$$\frac{5}{6}$$ = $$\frac{43}{42}$$.

Explanation:
The difference between 5$$\frac{6}{7}$$ – 4$$\frac{5}{6}$$ is $$\frac{41}{7}$$ – $$\frac{29}{6}$$
= $$\frac{246-203}{42}$$
= $$\frac{43}{42}$$.

Question 10.

6$$\frac{7}{8}$$ – 1$$\frac{2}{3}$$ = $$\frac{121}{24}$$.
The difference between 6$$\frac{7}{8}$$ – 1$$\frac{2}{3}$$ is $$\frac{55}{8}$$ – $$\frac{5}{3}$$
= $$\frac{165-40}{24}$$
= $$\frac{121}{24}$$.