# McGraw Hill Math Grade 5 Chapter 6 Lesson 6 Answer Key Adding Mixed Numbers with Unlike Denominators

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Lesson 6 Adding Mixed Numbers with Unlike Denominators are as per the latest syllabus guidelines.

## McGraw-Hill Math Grade 5 Answer Key Chapter 6 Lesson 6 Adding Mixed Numbers with Unlike Denominators

Solve

Find equivalent fractions and add. Change improper fractions to mixed numbers.

Question 1.
1$$\frac{1}{4}$$ + $$\frac{1}{6}$$ ________________
1$$\frac{3}{12}$$ + $$\frac{2}{12}$$ = 1$$\frac{5}{12}$$

Question 2.
1$$\frac{2}{3}$$ + $$\frac{1}{2}$$ _______________
$$\frac{10}{6}$$+$$\frac{4}{6}$$  = 2$$\frac{1}{3}$$.

Explanation:
The equivalent fraction of $$\frac{5}{3}$$ + $$\frac{1}{2}$$ which is $$\frac{10}{6}$$ and $$\frac{4}{6}$$. So the addition of $$\frac{10}{6}$$+$$\frac{4}{6}$$ is $$\frac{10+4}{6}$$
= $$\frac{14}{6}$$
= 2$$\frac{2}{6}$$
= 2$$\frac{1}{3}$$.

Question 3.
2$$\frac{1}{4}$$ + 3$$\frac{5}{8}$$ _______________
$$\frac{18}{8}$$+$$\frac{29}{8}$$ = 5$$\frac{7}{8}$$.

Explanation:
The equivalent fraction of $$\frac{9}{4}$$ + $$\frac{29}{8}$$ which is $$\frac{18}{8}$$ and $$\frac{29}{8}$$. So the addition of $$\frac{18}{8}$$+$$\frac{29}{8}$$ is $$\frac{18+29}{8}$$
= $$\frac{47}{8}$$
= 5$$\frac{7}{8}$$.

Question 4.
2$$\frac{1}{9}$$ + $$\frac{5}{6}$$ ________________
$$\frac{114}{54}$$+$$\frac{45}{54}$$ = 2$$\frac{1}{9}$$.

Explanation:
The equivalent fraction of $$\frac{19}{9}$$ + $$\frac{5}{6}$$ which is $$\frac{114}{54}$$ and $$\frac{45}{54}$$. So the addition of $$\frac{114}{54}$$+$$\frac{45}{54}$$ is $$\frac{114+45}{54}$$
= $$\frac{159}{54}$$
= 2$$\frac{6}{54}$$ = 2$$\frac{1}{9}$$.

Question 5.
4$$\frac{3}{8}$$ + 2$$\frac{1}{6}$$ ________________
$$\frac{210}{48}$$+$$\frac{104}{48}$$ = 6$$\frac{13}{16}$$.

Explanation:
The equivalent fraction of $$\frac{35}{8}$$ + $$\frac{13}{6}$$ which is $$\frac{210}{48}$$ and $$\frac{104}{48}$$. So the addition of $$\frac{210}{48}$$+$$\frac{104}{48}$$ is $$\frac{210+104}{8}$$
= $$\frac{314}{48}$$ =6$$\frac{26}{48}$$
= 6$$\frac{13}{16}$$.

Question 6.
1$$\frac{1}{5}$$ + 1$$\frac{1}{2}$$ ________________

$$\frac{18}{8}$$+$$\frac{29}{8}$$ = 5$$\frac{7}{8}$$.

Explanation:
The equivalent fraction of $$\frac{9}{4}$$ + $$\frac{29}{8}$$ which is $$\frac{18}{8}$$ and $$\frac{29}{8}$$. So the addition of $$\frac{18}{8}$$+$$\frac{29}{8}$$ is $$\frac{18+29}{8}$$
= $$\frac{47}{8}$$

Question 7.

$$\frac{49}{14}$$+$$\frac{20}{14}$$= 1$$\frac{7}{16}$$.

Explanation:
The equivalent fraction of $$\frac{7}{2}$$ + $$\frac{10}{7}$$ which is $$\frac{49}{14}$$ and $$\frac{20}{14}$$. So the addition of $$\frac{49}{14}$$+$$\frac{20}{14}$$ is $$\frac{49+20}{48}$$
= $$\frac{69}{48}$$ = 1$$\frac{21}{48}$$
= 1$$\frac{7}{16}$$.

Question 8.

$$\frac{35}{15}$$+$$\frac{24}{15}$$ = 3$$\frac{14}{15}$$.

Explanation:
The equivalent fraction of $$\frac{7}{3}$$ + $$\frac{8}{5}$$ which is $$\frac{35}{15}$$ and $$\frac{24}{15}$$. So the addition of $$\frac{35}{15}$$+$$\frac{24}{15}$$ is $$\frac{35+24}{15}$$
= $$\frac{59}{15}$$
= 3$$\frac{14}{15}$$.

Question 9.

$$\frac{376}{56}$$+$$\frac{344}{56}$$ = 12$$\frac{6}{7}$$.

Explanation:
The equivalent fraction of $$\frac{47}{7}$$ + $$\frac{43}{8}$$ which is $$\frac{376}{56}$$ and $$\frac{344}{56}$$. So the addition of $$\frac{376}{56}$$+$$\frac{344}{56}$$ is $$\frac{376+344}{56}$$
= $$\frac{720}{56}$$ = $$\frac{90}{7}$$
= 12$$\frac{6}{7}$$.

Question 10.

$$\frac{150}{42}$$+$$\frac{175}{42}$$ = 7$$\frac{31}{42}$$.
The equivalent fraction of $$\frac{25}{7}$$ + $$\frac{25}{6}$$ which is $$\frac{150}{42}$$ and $$\frac{175}{42}$$. So the addition of $$\frac{150}{42}$$+$$\frac{175}{42}$$ is $$\frac{150+175}{42}$$
= $$\frac{325}{42}$$
= 7$$\frac{31}{42}$$.