McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators

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All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Lesson 4 Subtracting Fractions with Like Denominators are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 6 Lesson 4 Subtracting Fractions with Like Denominators

Solve

Subtract. Give the answer in simplest terms.

Question 1.
\(\frac{3}{4}\) – \(\frac{1}{4}\) ______________
Answer:
\(\frac{2}{4}\) = \(\frac{1}{2}\)

Question 2.
\(\frac{11}{16}\) – \(\frac{3}{16}\) ______________
Answer:
\(\frac{11}{16}\) – \(\frac{3}{16}\) = \(\frac{1}{2}\).

Explanation:
The difference between \(\frac{11}{16}\) – \(\frac{3}{16}\) is \(\frac{11-3}{16}\)
= \(\frac{8}{16}\)
= \(\frac{1}{2}\).

Question 3.
\(\frac{6}{7}\) – \(\frac{3}{7}\) ______________
Answer:
\(\frac{6}{7}\) – \(\frac{3}{7}\) = \(\frac{3}{7}\).

Explanation:
The difference between \(\frac{6}{7}\) – \(\frac{3}{7}\) is \(\frac{6-3}{7}\)
= \(\frac{3}{7}\).

Question 4.
\(\frac{5}{8}\) – \(\frac{3}{8}\) ______________
Answer:
\(\frac{5}{8}\) – \(\frac{3}{8}\) = \(\frac{1}{4}\).

Explanation:
The difference between \(\frac{5}{8}\) – \(\frac{3}{8}\) is \(\frac{5-3}{8}\)
= \(\frac{2}{8}\)
= \(\frac{1}{4}\).

Question 5.
\(\frac{13}{16}\) – \(\frac{7}{16}\) ______________
Answer:
\(\frac{13}{16}\) – \(\frac{7}{16}\) = \(\frac{3}{8}\).

Explanation:
The difference between \(\frac{13}{16}\) – \(\frac{7}{16}\) is \(\frac{13-7}{16}\)
= \(\frac{6}{16}\)
= \(\frac{3}{8}\).

Question 6.
\(\frac{21}{37}\) – \(\frac{4}{37}\) ______________
Answer:
\(\frac{21}{37}\) – \(\frac{4}{37}\) = \(\frac{17}{37}\).

Explanation:
The difference between \(\frac{21}{37}\) – \(\frac{4}{37}\) is \(\frac{21-4}{37}\)
= \(\frac{17}{37}\).

Question 7.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 9
Answer:
\(\frac{17}{31}\) – \(\frac{7}{31}\) = \(\frac{10}{31}\).

Explanation:
The difference between \(\frac{17}{31}\) – \(\frac{7}{31}\) is \(\frac{17-7}{31}\)
= \(\frac{10}{31}\).

Question 8.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 10
Answer:
\(\frac{2}{9}\) – \(\frac{1}{9}\) = \(\frac{1}{9}\).

Explanation:
The difference between \(\frac{2}{9}\) – \(\frac{1}{9}\) is \(\frac{2-1}{9}\)
= \(\frac{1}{9}\).

Question 9.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 11
Answer:
\(\frac{27}{53}\) – \(\frac{6}{53}\) = \(\frac{21}{53}\).

Explanation:
The difference between \(\frac{27}{53}\) – \(\frac{6}{53}\) is \(\frac{27-6}{53}\)
= \(\frac{21}{53}\).

Question 10.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 12
Answer:
\(\frac{19}{29}\) – \(\frac{14}{29}\) = \(\frac{5}{29}\).

Explanation:
The difference between \(\frac{19}{29}\) – \(\frac{14}{29}\) is \(\frac{19-14}{29}\)
= \(\frac{5}{29}\).

Question 11.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 13
Answer:
\(\frac{7}{8}\) – \(\frac{5}{8}\) = \(\frac{1}{4}\).

Explanation:
The difference between \(\frac{7}{8}\) – \(\frac{5}{8}\) is \(\frac{7-5}{8}\)
= \(\frac{2}{8}\)
= \(\frac{1}{4}\).

Question 12.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 14
Answer:
\(\frac{8}{15}\) – \(\frac{1}{15}\) = \(\frac{7}{15}\).

Explanation:
The difference between \(\frac{8}{15}\) – \(\frac{1}{15}\) is \(\frac{8-1}{15}\)
= \(\frac{7}{15}\).

Question 13.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 15
Answer:
\(\frac{24}{35}\) – \(\frac{13}{35}\) = \(\frac{11}{35}\).

Explanation:
The difference between \(\frac{24}{35}\) – \(\frac{13}{35}\) is \(\frac{24-13}{35}\)
= \(\frac{11}{35}\).

Question 14.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 16
Answer:
\(\frac{7}{15}\) – \(\frac{2}{15}\) = \(\frac{1}{3}\).

Explanation:
The difference between \(\frac{7}{15}\) – \(\frac{2}{15}\) is \(\frac{7-2}{15}\)
= \(\frac{5}{15}\)
= \(\frac{1}{3}\).

Question 15.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 17
Answer:
\(\frac{38}{77}\) – \(\frac{25}{77}\) = \(\frac{13}{77}\).

Explanation:
The difference between \(\frac{38}{77}\) – \(\frac{25}{77}\) is \(\frac{38-25}{77}\)
= \(\frac{13}{77}\).

Question 16.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 18
Answer:
\(\frac{7}{24}\) – \(\frac{5}{24}\) = \(\frac{1}{12}\).

Explanation:
The difference between \(\frac{7}{24}\) – \(\frac{5}{24}\) is \(\frac{7-5}{24}\)
= \(\frac{2}{24}\)
= \(\frac{1}{12}\).

Question 17.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 19
Answer:
\(\frac{43}{65}\) – \(\frac{38}{65}\) = \(\frac{1}{13}\).

Explanation:
The difference between \(\frac{43}{65}\) – \(\frac{38}{65}\) is \(\frac{43-38}{65}\)
= \(\frac{5}{65}\)
= \(\frac{1}{13}\).

Question 18.
McGraw Hill Math Grade 5 Chapter 6 Lesson 4 Answer Key Subtracting Fractions with Like Denominators 20
Answer:
\(\frac{15}{16}\) – \(\frac{11}{16}\) = \(\frac{1}{4}\).

Explanation:
The difference between \(\frac{15}{16}\) – \(\frac{11}{16}\) is \(\frac{15-11}{16}\)
= \(\frac{4}{16}\)
= \(\frac{1}{4}\).

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