All the solutions provided in **McGraw Hill Math Grade 5 Answer Key PDF Chapter 6 Lesson 2 Finding Equivalent Fractions **are as per the latest syllabus guidelines.

## McGraw-Hill Math Grade 5 Answer Key Chapter 6 Lesson 2 Finding Equivalent Fractions

**Solve**

**Find the equivalent fraction.**

Question 1.

equivalent to \(\frac{1}{2}\), denominator 16 ______________

Answer:

\(\frac{8}{16}\)

Question 2.

equivalent to \(\frac{1}{3}\), denominator 12 ______________

Answer:

\(\frac{4}{12}\).

Explanation:

The equivalent fraction of \(\frac{1}{3}\) by denominator 12 is by multiplying numerator and denominator with 4. So \(\frac{1}{3}\) × \(\frac{4}{4}\) = \(\frac{4}{12}\).

Question 3.

equivalent to \(\frac{1}{5}\), denominator 20 ______________

Answer:

\(\frac{5}{20}\).

Explanation:

The equivalent fraction of \(\frac{1}{5}\) by denominator 20 is by multiplying numerator and denominator with 5. So \(\frac{1}{5}\) × \(\frac{5}{5}\) = \(\frac{5}{20}\).

Question 4.

equivalent to \(\frac{2}{3}\), denominator 15 ______________

Answer:

\(\frac{10}{15}\).

Explanation:

The equivalent fraction of \(\frac{2}{3}\) by denominator 15 is by multiplying numerator and denominator with 5. So \(\frac{2}{3}\) × \(\frac{5}{5}\) = \(\frac{10}{15}\).

Question 5.

equivalent to \(\frac{3}{4}\), denominator 12 ______________

Answer:

\(\frac{9}{12}\).

Explanation:

The equivalent fraction of \(\frac{3}{4}\) by denominator 12 is by multiplying numerator and denominator with 3. So \(\frac{3}{4}\) × \(\frac{3}{3}\) = \(\frac{9}{12}\).

Question 6.

equivalent to \(\frac{3}{4}\), denominator 16 ______________

Answer:

\(\frac{12}{16}\).

Explanation:

The equivalent fraction of \(\frac{3}{4}\) by denominator 16 is by multiplying numerator and denominator with 4. So \(\frac{3}{4}\) × \(\frac{4}{4}\) = \(\frac{12}{16}\).

Question 7.

equivalent to \(\frac{3}{5}\), denominator 20 ______________

Answer:

\(\frac{15}{20}\).

Explanation:

The equivalent fraction of \(\frac{3}{5}\) by denominator 20 is by multiplying numerator and denominator with 5. So \(\frac{3}{5}\) × \(\frac{5}{5}\) = \(\frac{15}{20}\).

Question 8.

equivalent to \(\frac{5}{12}\), denominator 24 ______________

Answer:

\(\frac{10}{24}\).

Explanation:

The equivalent fraction of \(\frac{1}{3}\) by denominator 24 is by multiplying numerator and denominator with 2. So \(\frac{5}{12}\) × \(\frac{2}{2}\) = \(\frac{10}{24}\).

Question 9.

equivalent to \(\frac{4}{5}\), denominator 30 ______________

Answer:

\(\frac{24}{30}\).

Explanation:

The equivalent fraction of \(\frac{4}{5}\) by denominator 30 is by multiplying numerator and denominator with 6. So \(\frac{4}{5}\) × \(\frac{6}{6}\) = \(\frac{24}{30}\).

Question 10.

equivalent to \(\frac{5}{7}\), denominator 49 ______________

Answer:

\(\frac{35}{49}\).

Explanation:

The equivalent fraction of \(\frac{5}{7}\) by denominator 49 is by multiplying numerator and denominator with 7. So \(\frac{5}{7}\) × \(\frac{7}{7}\) = \(\frac{35}{49}\).