McGraw Hill Math Grade 5 Chapter 11 Lesson 2 Answer Key Using Line Plots to Solve Problems

All the solutions provided in McGraw Hill Math Grade 5 Answer Key PDF Chapter 11 Lesson 2 Using Line Plots to Solve Problems are as per the latest syllabus guidelines.

McGraw-Hill Math Grade 5 Answer Key Chapter 11 Lesson 2 Using Line Plots to Solve Problems

Solve

Use the line plot above for exercises 1-6. 

Question 1.
What is the difference between the tallest plant and the shortest plant shown on the line plot?
2\(\frac{1}{4}\)in.

Question 2.
What is the sum of the height of the two tallest plants?
Answer:
The height of the first tallest plant is 43\(\frac{1}{2}\)in.
The height of the second tallest plant is 43\(\frac{1}{4}\)in.
43\(\frac{1}{2}\)in + 43\(\frac{1}{4}\)in = 86\(\frac{3}{4}\)in
The sum of the height of the two tallest plants is 86\(\frac{3}{4}\)in.

Question 3.
How many plants are 42\(\frac{1}{2}\) in. tall? ________
What is the total sum of their height?
Answer:
Four plants are 42\(\frac{1}{2}\) in tall.
The four plants height is each 42\(\frac{1}{2}\) in tall.
42\(\frac{1}{2}\) in + 42\(\frac{1}{2}\) in  + 42\(\frac{1}{2}\) in  + 42\(\frac{1}{2}\) in = 168 4/2 in or 170 in.
The total sum of their height is 170 inches.

Question 4.
What is the total height of the three shortest plants?
Answer:
The first shortest plant is 41\(\frac{1}{4}\) in.
The second shortest plant is 42 in.
The third shortest plant is 42\(\frac{1}{4}\) in.
41\(\frac{1}{4}\) in + 42 in + 42\(\frac{1}{4}\) in = 125 \(\frac{2}{4}\) in or 125\(\frac{1}{2}\) in
The total height of the three shortest plants is 125\(\frac{1}{2}\) in.

Question 5.
Which height is an outlier?
Answer:
The height 41\(\frac{1}{4}\) inches is an outlier.

Question 6.
To find the average height, you would find the sum of all the heights shown and then divide by the number of plants. What is the average height shown on the line plot?
Answer:
The sum of all the heights are as below
41\(\frac{1}{4}\) in + 42 + 42\(\frac{1}{4}\) in + 170 + 84\(\frac{3}{4}\) in + 43 + 43\(\frac{1}{4}\) in + 43\(\frac{1}{2}\) in = 510
Average height shown on the line plot = Sum of all the heights/ Number of plants
Number of plants = 12
Average height shown on the line plot = 510/12 = 42.5 in or 42 9/16 in

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