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McGraw-Hill Math Grade 3 Answer Key Chapter 3 Lesson 6 Estimating Sums
Estimate
Estimate each sum. Round each addend to the nearest ten. Then add.
Question 1.
Answer:
53 + 71 = 124.
Explanation:
Nearest ten of:
53 = 50.
71 = 70.
50 + 70 = 120.
Question 2.
Answer:
35 + 92 = 127.
Explanation:
Nearest ten of:
35 = 40.
92 = 90.
40 + 90 = 130.
Question 3.
Answer:
48 + 15 = 63.
Explanation:
Nearest ten of:
48 = 50.
15 = 20.
50 + 20 = 70.
Estimate each sum. Round each addend to the nearest hundred. Then add.
Question 4.
Answer:
232 + 785 = 1,017.
Explanation:
Nearest hundred of:
232 = 200.
785 = 800.
200 + 800 = 1,000.
Question 5.
Answer:
552 + 174 = 726.
Explanation:
Nearest hundred of:
552 = 600.
174 = 200.
600 + 200 = 800.
Question 6.
Answer:
327 + 563 = 890.
Explanation:
Nearest hundred of:
327 = 300.
563 = 600.
300 + 600 = 900.
Estimate each sum. Round each addend. Then add.
Question 7.
Tyrell sold 23 cars in his first month as a car salesman. He sold 15 cars in his second month. He sold 38 cars this month. About how many cars did Tyrell sell in three months?
Answer:
Total number of cars Tyrell sold in three months = 76.
Explanation:
Number of cars Tyrell sold in his first month as a car salesman = 23.
Number of cars Tyrell sold in his second month as a car salesman = 15.
Number of cars Tyrell sold in this month as a car salesman = 38.
Total number of cars Tyrell sold in three months = Number of cars Tyrell sold in his first month as a car salesman + Number of cars Tyrell sold in his second month as a car salesman + Number of cars Tyrell sold in this month as a car salesman
= 23 + 15 + 38
= 38 + 38
= 76.